Use Logarithmic Differentiation To Find The Derivative Of Y

Next Genwave
Mar 10, 2025 · 6 min read

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Use Logarithmic Differentiation to Find the Derivative of y
Logarithmic differentiation is a powerful technique in calculus used to find the derivatives of complex functions, particularly those involving products, quotients, and powers of functions. It simplifies the differentiation process by utilizing the properties of logarithms to transform a complicated expression into a more manageable form. This method is especially beneficial when dealing with functions that are difficult or impossible to differentiate using standard rules. This comprehensive guide will explore the intricacies of logarithmic differentiation, providing a step-by-step approach and numerous examples to solidify your understanding.
Understanding the Power of Logarithms
Before diving into the technique, let's refresh our understanding of logarithmic properties. These properties are the foundation upon which logarithmic differentiation rests:
- Product Rule: log<sub>b</sub>(xy) = log<sub>b</sub>x + log<sub>b</sub>y
- Quotient Rule: log<sub>b</sub>(x/y) = log<sub>b</sub>x - log<sub>b</sub>y
- Power Rule: log<sub>b</sub>(x<sup>n</sup>) = n log<sub>b</sub>x
These rules allow us to break down complex expressions into simpler sums and differences of logarithms, making differentiation significantly easier. We will predominantly use the natural logarithm (ln), with base e, due to its convenient derivative (d/dx ln x = 1/x).
The Logarithmic Differentiation Process: A Step-by-Step Guide
The process of logarithmic differentiation involves the following steps:
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Take the natural logarithm of both sides: If you have a function y = f(x), start by taking the natural logarithm of both sides: ln y = ln[f(x)].
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Apply logarithmic properties: Use the properties of logarithms to simplify the expression on the right-hand side. This often involves expanding products, quotients, and powers using the rules mentioned above. This step significantly simplifies the expression, making differentiation easier.
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Differentiate implicitly with respect to x: Differentiate both sides of the equation with respect to x. Remember to use the chain rule when differentiating ln y (d/dx ln y = (1/y)(dy/dx)).
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Solve for dy/dx: After differentiating, manipulate the equation algebraically to isolate dy/dx, which represents the derivative of the original function y with respect to x. This involves multiplying both sides by y and simplifying the resulting expression.
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Substitute back for y: Finally, substitute the original expression for y back into the equation to obtain the derivative in terms of x.
Illustrative Examples: Mastering Logarithmic Differentiation
Let's illustrate the technique with several examples, starting with simpler cases and progressing to more complex ones.
Example 1: A Simple Product
Find the derivative of y = x²(x+1)<sup>3</sup> using logarithmic differentiation.
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Take the natural logarithm: ln y = ln[x²(x+1)<sup>3</sup>]
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Apply logarithmic properties: ln y = 2ln x + 3ln(x+1)
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Differentiate implicitly: (1/y)(dy/dx) = 2(1/x) + 3(1/(x+1))
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Solve for dy/dx: dy/dx = y[2/x + 3/(x+1)]
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Substitute for y: dy/dx = x²(x+1)<sup>3</sup>[2/x + 3/(x+1)] This can be further simplified if desired.
Example 2: A Quotient with Powers
Find the derivative of y = (x<sup>3</sup> + 2x)/(x<sup>2</sup> - 1)<sup>1/2</sup> using logarithmic differentiation.
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Take the natural logarithm: ln y = ln[(x<sup>3</sup> + 2x)/(x<sup>2</sup> - 1)<sup>1/2</sup>]
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Apply logarithmic properties: ln y = ln(x<sup>3</sup> + 2x) - (1/2)ln(x<sup>2</sup> - 1)
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Differentiate implicitly: (1/y)(dy/dx) = (3x<sup>2</sup> + 2)/(x<sup>3</sup> + 2x) - (1/2)[(2x)/(x<sup>2</sup> - 1)]
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Solve for dy/dx: dy/dx = y[(3x<sup>2</sup> + 2)/(x<sup>3</sup> + 2x) - x/(x<sup>2</sup> - 1)]
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Substitute for y: dy/dx = [(x<sup>3</sup> + 2x)/(x<sup>2</sup> - 1)<sup>1/2</sup>][(3x<sup>2</sup> + 2)/(x<sup>3</sup> + 2x) - x/(x<sup>2</sup> - 1)]
Example 3: A More Complex Function
Find the derivative of y = x<sup>x</sup> using logarithmic differentiation. Note that this is an example of a function raised to a function of x.
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Take the natural logarithm: ln y = ln(x<sup>x</sup>)
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Apply logarithmic properties: ln y = x ln x
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Differentiate implicitly: (1/y)(dy/dx) = ln x + x(1/x) = ln x + 1
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Solve for dy/dx: dy/dx = y(ln x + 1)
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Substitute for y: dy/dx = x<sup>x</sup>(ln x + 1)
Example 4: Dealing with Trigonometric Functions
Find the derivative of y = sin x<sup>cos x</sup>. This demonstrates the application of logarithmic differentiation to trigonometric functions.
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Take the natural logarithm: ln y = ln(sin x<sup>cos x</sup>)
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Apply logarithmic properties: ln y = cos x ln(sin x)
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Differentiate implicitly: (1/y)(dy/dx) = -sin x ln(sin x) + cos x (cos x / sin x) = -sin x ln(sin x) + cos²x / sin x
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Solve for dy/dx: dy/dx = y[-sin x ln(sin x) + cos²x / sin x]
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Substitute for y: dy/dx = sin x<sup>cos x</sup>[-sin x ln(sin x) + cos²x / sin x]
When to Use Logarithmic Differentiation
Logarithmic differentiation is particularly useful in the following scenarios:
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Functions involving multiple products and quotients: Simplifying these complex expressions using logarithmic properties significantly reduces the complexity of applying the product and quotient rules repeatedly.
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Functions with variables in both the base and exponent: Examples like x<sup>x</sup>, where standard differentiation rules are not directly applicable, benefit greatly from this technique.
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Functions that are difficult to simplify before differentiation: Logarithmic differentiation allows you to simplify the expression first, making the differentiation process far more manageable.
Common Mistakes to Avoid
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Forgetting the chain rule: Remember to apply the chain rule when differentiating ln y. This is a crucial step in the process.
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Incorrectly applying logarithmic properties: Ensure you correctly apply the product, quotient, and power rules of logarithms. A mistake here will lead to an incorrect derivative.
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Not substituting back for y: After solving for dy/dx, remember to substitute the original expression for y to express the derivative in terms of x.
Conclusion: Mastering a Powerful Tool
Logarithmic differentiation provides a valuable alternative to standard differentiation techniques, particularly for complex functions. By mastering this method, you equip yourself with a powerful tool to tackle a wide range of differentiation problems efficiently and accurately. Remember to practice regularly with diverse examples to build your proficiency and confidence in applying this essential calculus technique. Through consistent practice and understanding of the underlying principles, you'll find logarithmic differentiation an invaluable asset in your calculus journey.
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